\sqrt(9.8)~ 3.13
3v/ 2 ~ 4.2
To find the p-value for a parabola given its focus and directrix, first identify the coordinates of the focus (F) and the equation of the directrix (a line). The p-value represents the distance from the vertex of the parabola to the focus (or the vertex to the directrix), which is half the distance between them. Calculate this distance using the formula for distance between a point and a line, or by measuring the distance from the vertex to either the focus or the directrix. The p-value is then the absolute value of this distance.
The first step in constructing a line parallel to line AB through point P is to use a straightedge or ruler to draw a line from point P to line AB, ensuring that it intersects at some point. Next, using a compass, measure the angle between line AB and the line drawn from P, and then replicate that angle on the opposite side of point P to establish the direction of the parallel line. Finally, draw a line through point P in the direction of this angle, ensuring it remains parallel to line AB.
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To find the image of point C after a 180-degree counterclockwise rotation about point P, you first identify the coordinates of both points. Then, you reflect point C across point P, effectively moving it to the opposite side of P at an equal distance. The resulting image will be directly opposite C in relation to P, forming a straight line through P.
The perpendicular bisector of the line segment connecting points ( A ) and ( B ) in the plane is a line that divides the segment into two equal parts at a right angle. Every point on this line is equidistant from points ( A ) and ( B ). This means that if you take any point ( P ) on the perpendicular bisector, the distance from ( P ) to ( A ) will be the same as the distance from ( P ) to ( B ). Thus, the perpendicular bisector is the locus of points satisfying this equidistance condition.
It depends on how complicated you want to make it. The generally accepted answer would be to start at one point, and make a line to the next (a straight line). That's gonna be the answer, say, your teacher might want (sorry if you're an adult :p). The technical answer? Drill a hole through the globe from one point to the other, and your shortest distance would be the straight line. Einstein's answer? A geodesic. Look it up :p
To find the reflection of point P(-1, 6) across the line y = x, you swap the x and y coordinates of the point. Therefore, the reflection of P(-1, 6) is P'(6, -1).
P = the distance around a figure. A = the surface it takes up.
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Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)