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The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
Depending on the figure given you can find the area from the perimeter For example- If you have a square with a perimeter of 24, you divide 24 by 4 because all the sides of a square are congruent. In turn you will 6 as each side of the square The formula for the area of a square is side2 so you get 62 which is 36. The area is 36
Perimeter = 4 times the square root of the area.
The perimeter is 44 units.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.
Given a 56 cm diagonal, the square will have a perimeter of 158.4 cm
There are no units given for the multiplications; are they:The same unitsThe multiplications could be the areas of rectangles which means the results will be SQUARE unitswhich means if the difference required is in feet and NOT SQUARE feet, is it the difference in perimeter of the two rectangles?I think you need to re-ask your question with proper units included, then we can possibly answer it.
If you are given the area, A square units, then each side of the square is sqrt(A) units. And then the perimeter is 4*sqrt(A) units. The smaller square inside is irrelevant.
Perimeter of a square is given by 4a where 'a' is the side of square. Just put 64 equals to 4a which gives a=16
square
The square is.