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The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.

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Q: What is the maximum area for a rectangle whose perimeter is 136?

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The perimeter of the rectangle is the sum of its 4 sides.

find the perimeter and area of a rectangle that is 15cm long and 5cm wide

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.

the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle

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that's easy.....it's 1 ;)

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