The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).
If the length of each edge of the cube is 's',then the area of each face is s2.
Type answer here.
Base 7m area 49 m2
Area of base 18m2 Area of each side 12m2 Total area 54m2
Because it is the square units around the base.
find the area of a rectangle with base 4 ft and height 4 in?
To calculate the surface area of a regular pyramid, you need to find the area of the base and the area of the triangular faces. The surface area (SA) can be expressed as SA = Base Area + Lateral Area. For a square base, the base area is the side length squared, and the lateral area is found by calculating the area of each triangular face and summing them. If you provide the base side length and the height of the pyramid, I can help calculate the exact surface area.
Formula for area of Triangle: a=0.5(bh) Where b is the base length and h is the height. For example, a triangle of base 10 and height 5 has an area of 25.
If you draw a diagonal in a rectangle you get two equal triangles, each half the area of the rectangle. Area of rectangle is base x height, so half of that is ½ x base x height. QED
The area of a triangle is half the area of a quadrilateral when the quadrilateral is divided into two triangles by drawing a diagonal. Since both triangles share the same base and height (the height being perpendicular to the base), the area of each triangle is equal to half the area of the quadrilateral. Therefore, for any quadrilateral, its area is double that of each of the triangles formed by its diagonal.
You cannot. There are infinitely many possible parallelograms whose area is 135 square units, each with a different base (and so a different height).