Use Pythagoras.
d^2 = ( x - x(1))^2 + ( y - y(1))^2
Substituting (13,-17) & ( -10.-17)
d^2 = ( 13 - - 10)^2 + ( -17--17)^2
d^2 = 23^2 + 0^2
d^2 = 23^2
d = 23
The distance between these two points is 23.
If you mean points of: (2, 1) and (14, 6) then the distance is 13
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
If you mean points of (5, 5) and (1, 5) then the distance is 4
Points: (2, 1) and (14, 6) Distance: 13
10 units
18 units
Distance between the points of (3, 7) and (15, 16) is 15 units
The distance between points: (9, 4) and (3, 4) is 6
Points: (2, 3) and (2, 7) Distance works out as: 4 units
If you mean points of (5, 5) and (1, 5) then the distance is 4
(Distance between the points)2 = (difference of the two x-values)2 + (difference of the two y-values)2