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What is the distance between the points (13 , -17) and (-10 , -17) in the coordinate plane?
Updated: 10/17/2024
Use Pythagoras.
d^2 = ( x - x(1))^2 + ( y - y(1))^2
Substituting (13,-17) & ( -10.-17)
d^2 = ( 13 - - 10)^2 + ( -17--17)^2
d^2 = 23^2 + 0^2
d^2 = 23^2
d = 23
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