As written this appear to be 'Long Multiplication.
321
x 14
3210 ( 1st Part) ; (Multiply by '10')
1284 (2nd part) ; (Multiply by '4')
Add ( 10 + 4 = 14)
=4494 the answer!!!!
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how to find the partial products of a number
the partial products for 12 and 3 30 and 6 :)
5630 is a single number and single numbers do not have partial products.
the partial products is 2,480 and 310
Partial products cannot be used for a single number. They are a form of multiplication.
700 and 210 are the answers to partial products of 77 times 30
32114 32117 32118
The number of partial products in multiplication depends on the number of digits in the factors being multiplied. In 1(a), if there are three digits in one factor, each digit contributes a partial product when multiplied by the other factor, resulting in three partial products. In 1(b), if one factor has two digits, it will produce only two partial products corresponding to its two digits. Thus, the difference in the number of partial products reflects the number of digits in the factors being multiplied.
How does adding partial products help solve a multiplication problem
A single number, such as 4228, cannot have partial fractions.
k
80,16