The pattern of odd numbers
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5
37, this sequence counts up from 5 the difference between 2 and 7. the difference between 20 and 28 is 8 making the next number 9, and 28 and 9 = 37.
Willies
20
yes it is
70 - (20 - 13)
13 + 7 = 20 13 - 7 = 6
37, 47, 58, 70, ... Each time the difference in the sequence increases by 1. From 2 to 7, we increase by 5 From 7 to 13, we increase by 6 From 13 to 20, we increase by 7 From 20 to 28, we increase by 8 From 28 to 37, we increase by 9, etc..
It's, 7n+6
The 12 is - it should be 20.There are 2 interlocking sequences:the first, third, fifth, etc digits belong to one sequence which is formed by adding 2 to the previous digit, starting with 5, as in: 5, 7, 9, 11, 13, 15, etcthe second, fourth, sixth, etc digits belong to the other sequence which is formed by adding 9 to the previous digit, starting with 2, as in: 2, 11, 20, 29. 38, 47, etc.So the sixth digit of the original sequence is 12, but should be 20, the third digit of the second sequence.
No it wouldn't.
6 and 10