The sequence 6, 13, 20, 27 increases by 7 each time. This indicates it is an arithmetic sequence with a common difference of 7. The nth term can be expressed as ( a_n = 6 + 7(n-1) ), which simplifies to ( a_n = 7n - 1 ). Thus, the nth term is ( 7n - 1 ).
The sequence 13, 20, 27, 34, 41 is an arithmetic sequence with a common difference of 7. The nth term formula can be expressed as ( a_n = 13 + (n - 1) \times 7 ). Simplifying this, we get ( a_n = 7n + 6 ). Thus, the nth term is given by ( a_n = 7n + 6 ).
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
There is no pattern
arrange the no. ascending and use the formula (n+1)/2=nth number...arranged no. :20 23 25 25 27 27 27 29 31 35 37 41 43n is the number of the numbers...substitute: (13+1)/2= 7th no. from the arranged numbers...so the answer 27
tn = 3n or 3*3* ... *3 (where there are n threes.)
Willies
The sequence 13, 20, 27, 34, 41 is an arithmetic sequence with a common difference of 7. The nth term formula can be expressed as ( a_n = 13 + (n - 1) \times 7 ). Simplifying this, we get ( a_n = 7n + 6 ). Thus, the nth term is given by ( a_n = 7n + 6 ).
Oh, dude, chill. The nth term for this sequence is -7n + 27. But like, who really needs to know that? Just enjoy the numbers, man.
The nth term of the sequence is (n + 1)2 + 2.
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
2n +29
5n+2
n3
The 38th term
The sequence 18, 27, 36, 45, 54 is an arithmetic sequence where each term increases by 9. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term (18) and ( d ) is the common difference (9). Thus, the nth term is ( a_n = 18 + (n-1) \times 9 = 9n + 9 ).
the anser is that you are stupid
3^n These are powers of 3