To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
There is no pattern
tn = 3n or 3*3* ... *3 (where there are n threes.)
after -9 it is -15 then -21, -27 and the ninth is -36
arrange the no. ascending and use the formula (n+1)/2=nth number...arranged no. :20 23 25 25 27 27 27 29 31 35 37 41 43n is the number of the numbers...substitute: (13+1)/2= 7th no. from the arranged numbers...so the answer 27
Willies
Oh, dude, chill. The nth term for this sequence is -7n + 27. But like, who really needs to know that? Just enjoy the numbers, man.
The nth term of the sequence is (n + 1)2 + 2.
2n +29
5n+2
n3
The 38th term
3^n These are powers of 3
the anser is that you are stupid
9 3 1
There is no pattern
A single number, such as 1521273339 does not define a sequence. There is no nth term for a signle number.