0.6 & 5.6
Let x = one number
y = another number
Equations:
x * y = 3.36 .............. .....equation (1)
x - y = 5 .........................equation (2)
x = y + 5 ........................equation (3)
substitute eq. (3) to eq. (1)
x * y = 3.36
(y + 5) * y = 3.36
y2 + 5y = 3.36
y2 + 5y -3.36 = 0
Solving y by quadratic formula:
y = -5 √25 -4(1)(-3.36)/2
y = -5√38.44/2
y = (-5 + 6.2)/2
y = 0.6
Substitute y = 0.6 to eq. (2)
x - y = 5
x = y + 5
x = 0.6 + 5
x = 5.6
Check:
0.6 * 5.6 = 3.36
37
Your answer is 16 & 21 21 - 16 = 5 21 * 16 = 336
6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.
There are, of course, infinitely many solutions here. Choose any two positive numbers for the first two dimensions. Then divide 336 by the product of the two numbers, to get the third dimension.
The product is: 336
The product of prime numbers for 336 is:2x2x2x2x3x7This is because all of that sum equals the total of 3362x2x2x3x7=336
111 + 112 + 113 = 336
37
Your answer is 16 & 21 21 - 16 = 5 21 * 16 = 336
The LCM of these numbers is 336. LCM is Least Common Multiple.
6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.
There are, of course, infinitely many solutions here. Choose any two positive numbers for the first two dimensions. Then divide 336 by the product of the two numbers, to get the third dimension.
Let X be the second number. The first number, 21 is 6.25% of the product, which means that 21 is 0.0625*X. Solving for X, we get X = 21/(0.0625) = 336. Therefore, the second number is 336.
The product is 336
It is: 2*2*2*2*3*7 = 336
How about: 336
Every number is divisible by any non-zero number.Any element of the set of numbers of the form 336*k, where k is an integer, is evenly divisible.