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Q: Three consecutive numbers that have a product of 336?

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The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.

There are four consecutive odd integers: 81, 83, 85 and 87.

The product is 336

The integers are 81, 83, 85 and 87.

The prime factorization of 336 is: 2 * 2 * 2 * 2 * 3 * 7As a product its prime factors: 2*2*2*2*3*7 = 336

Related questions

The product of prime numbers for 336 is:2x2x2x2x3x7This is because all of that sum equals the total of 3362x2x2x3x7=336

111, 112 and 113.

37

6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.

Your answer is 16 & 21 21 - 16 = 5 21 * 16 = 336

The LCM of these numbers is 336. LCM is Least Common Multiple.

The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.

168, 336, 504

There are, of course, infinitely many solutions here. Choose any two positive numbers for the first two dimensions. Then divide 336 by the product of the two numbers, to get the third dimension.

There are four consecutive odd integers: 81, 83, 85 and 87.

x + x + 2 + x + 4 +x + 6 = 336 4x + 12 = 336 4x = 324 x = 81 81,83,85, 87

Let X be the second number. The first number, 21 is 6.25% of the product, which means that 21 is 0.0625*X. Solving for X, we get X = 21/(0.0625) = 336. Therefore, the second number is 336.