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What three consecutive odd numbers have a product of 29667?
Let's assume the first odd number is x. Then the next two consecutive odd numbers would be x + 2 and x + 4. The product of these three numbers is x(x + 2)(x + 4) = 29667. By trial and error, we find that x = 51 satisfies this equation. Therefore, the three consecutive odd numbers are 51, 53, and 55.
What 3 consecutive odd numbers have a product of 29667?
The numbers can be represented as n - 2, n and n + 2 so that (n - 2)n(n + 2) = 29667 This can be expressed as n(n2 - 4) = n3 - 4n = 39667 and the roots solved for a cubic equation. However, the problem can also be solved by factoring. If the numbers are a, b and c then a x b x c = 29667 and a, b and c are clearly factors of 29667. The factors of 29667 are 3 x 11 x 29 x 31 which can be stated as 33 x 29 x 31. The three consecutive numbers are therefore 29, 31 and 33.
What two consecutive odd numbers have a product of 12099?
The consecutive odd number with a product of 12099 are 109 and 111.
The product of 3 consecutive odd numbers make 6873 what is it?
There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.
What to consecutive numbers are the product of 195?
Do you mean what two consecutive odd numbers gives a product of 195? If so then: 13*15 = 195
What three consecutive odd numbers have a product of 29667?
Let's assume the first odd number is x. Then the next two consecutive odd numbers would be x + 2 and x + 4. The product of these three numbers is x(x + 2)(x + 4) = 29667. By trial and error, we find that x = 51 satisfies this equation. Therefore, the three consecutive odd numbers are 51, 53, and 55.
What three consecutive odd numbers have a sum of 29667?
The average of the three numbers will have to be 29667/3 = 9889. Taking one odd number from each side means that the three odd numbers in the sum would be 9887 + 9889 + 9891 = 29667.
What 3 consecutive odd numbers have a product of 29667?
The numbers can be represented as n - 2, n and n + 2 so that (n - 2)n(n + 2) = 29667 This can be expressed as n(n2 - 4) = n3 - 4n = 39667 and the roots solved for a cubic equation. However, the problem can also be solved by factoring. If the numbers are a, b and c then a x b x c = 29667 and a, b and c are clearly factors of 29667. The factors of 29667 are 3 x 11 x 29 x 31 which can be stated as 33 x 29 x 31. The three consecutive numbers are therefore 29, 31 and 33.
What two consecutive odd numbers have a product of 12099?
The consecutive odd number with a product of 12099 are 109 and 111.
The product of 3 consecutive odd numbers make 6873 what is it?
There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.
The product of which 3 consecutive odd numbers 6783?
17,19,21
Is the product of 2 consecutive numbers odd or even?
even
Product of 3 consecutive odd numbers is 6783?
17,19,21
What to consecutive numbers are the product of 195?
Do you mean what two consecutive odd numbers gives a product of 195? If so then: 13*15 = 195
What two consecutive number have a product of 324?
No two consecutive numbers have a product that is an even number. Any two consecutive numbers include one odd number and one even number. The product of one odd number and one even number is always an odd number.
What are consecutive odd numbers?
There are no two consecutive odd numbers.
The product of two consecutive odd natural numbers is 195 find the numbers?
15 and 13
