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JordanLet's assume the first odd number is x. Then the next two consecutive odd numbers would be x + 2 and x + 4. The product of these three numbers is x(x + 2)(x + 4) = 29667. By trial and error, we find that x = 51 satisfies this equation. Therefore, the three consecutive odd numbers are 51, 53, and 55.
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What 3 consecutive odd numbers have a product of 29667?
The numbers can be represented as n - 2, n and n + 2 so that (n - 2)n(n + 2) = 29667 This can be expressed as n(n2 - 4) = n3 - 4n = 39667 and the roots solved for a cubic equation. However, the problem can also be solved by factoring. If the numbers are a, b and c then a x b x c = 29667 and a, b and c are clearly factors of 29667. The factors of 29667 are 3 x 11 x 29 x 31 which can be stated as 33 x 29 x 31. The three consecutive numbers are therefore 29, 31 and 33.
What 3 consecutive composite numbers whose product of 192?
There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.
The product of three consecutive numbers is 60 What are the 3 numbers?
3 x 4 x 5 = 60 The three consecutive numbers are 3, 4, and 5.
What three consective numbers have a product of 105?
Three consecutive odd numbers: 3, 5, 7
What three consecutive whole numbers have a product of 29760?
The numbers are 30, 31 and 32.
