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What three consecutive odd numbers have a product of 29667?
Let's assume the first odd number is x. Then the next two consecutive odd numbers would be x + 2 and x + 4. The product of these three numbers is x(x + 2)(x + 4) = 29667. By trial and error, we find that x = 51 satisfies this equation. Therefore, the three consecutive odd numbers are 51, 53, and 55.
What 3 consecutive odd numbers have a product of 29667?
The numbers can be represented as n - 2, n and n + 2 so that (n - 2)n(n + 2) = 29667 This can be expressed as n(n2 - 4) = n3 - 4n = 39667 and the roots solved for a cubic equation. However, the problem can also be solved by factoring. If the numbers are a, b and c then a x b x c = 29667 and a, b and c are clearly factors of 29667. The factors of 29667 are 3 x 11 x 29 x 31 which can be stated as 33 x 29 x 31. The three consecutive numbers are therefore 29, 31 and 33.
What two consecutive odd numbers have a product of 12099?
The consecutive odd number with a product of 12099 are 109 and 111.
The product of 3 consecutive odd numbers make 6873 what is it?
There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.
What to consecutive numbers are the product of 195?
Do you mean what two consecutive odd numbers gives a product of 195? If so then: 13*15 = 195
