There is no such shape. If anyone can prove otherwise, I'd be grateful if they'd let me know.
One possible answer is an infinite cone. Spheres have one face but no vertex. No physical 3-D shape can have a vertex without having more than one face (a real cone typically has two: side and bottom).
An infinite cone.
No, a shape cannot have more than 3 edges meeting at a vertex and simultaneously have a right angled face. A right angled face implies that two edges form a right angle, which is only possible with three edges meeting at a vertex.
it has one vertex two circle edges and one face
A cone has 1 face, 0 edges, and one vertex. The face is the circular flat area. The cone can roll, so it has no edges. Edges have to be straight. The vertex is the pointy thing opposite to the face.
The shape can't exist: if you imagine a square face in 2D you have 4 edges and 4 vertices. Adding a further vertex out of the plane (introducing a 3rd dimension) you MUST have 4 more edges to join the original 4 vertices to the novel vertex. This sums to 8 edges as a minimum.This is of course assuming Euclidean geometry.
A teardrop-shape would have one vertex (the tip), one edge and one face
cone
An infinite cone.
It has eight edges, five faces, and one vertex.
Edges: 8 Faces: 5 Vertices: 5
one face one vertex and two circle edges * * * * * What kind of cone is that? It has 1 edge, 2 faces (one curved and one plane), and 1 vertex.