It could be a square based pyramid
It is a triangle with one right angled vertex.
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
No. Only 2 altitudes can intersect at a point. * * * * * True but even they do not meet in the interior. The altitudes of a right angles triangle meet at the right angled vertex. The vertex is at the boundary of the triangle, not in the interior.
They have 8 vertices, 12 edges and 6 faces. All edges meet at right angles. All faces meet at right angles. Every face is a rectangle (a square is a rectangle). The three vertex-to-opposite-vertex diagonals meet at a point which is the centre of gravity. This point bisects the diagonals.
A diagonal is normally defined as a straight line joining a vertex of a polygon with any vertex other than an adjoining vertex (lines joining a vertex to an adjoining vertex would simply be a side of the polygon). Since a triangle has only got adjoining vertices, it has no diagonals. Since there are no diagonals, they cannot bisect one another.
It is a triangle with one right angled vertex.
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
You can have a trapezium, a kite or an arrowhead with right angled vertices, as well as a completely irregular quadrilateral. In fact, any kind of quadrilateral other than a parallelogram (or rhombus) can have a right angled vertex.
No. Only 2 altitudes can intersect at a point. * * * * * True but even they do not meet in the interior. The altitudes of a right angles triangle meet at the right angled vertex. The vertex is at the boundary of the triangle, not in the interior.
On an obtuse triangle the orthocenter is located on the outside of the triangle and the orthocenter of the right triangle is located at the vertex of the triangle ...
If you make one side the base the opposite vertex is the apex, so there are three possible apices.
hemisphere
Oh, dude, let me break it down for you. So, each vertex has degree 2, which means each vertex is connected to two edges. Since there are 7 vertices, you would have 7 * 2 = 14 edges in total. Easy peasy, right?
They have 8 vertices, 12 edges and 6 faces. All edges meet at right angles. All faces meet at right angles. Every face is a rectangle (a square is a rectangle). The three vertex-to-opposite-vertex diagonals meet at a point which is the centre of gravity. This point bisects the diagonals.
A diagonal is normally defined as a straight line joining a vertex of a polygon with any vertex other than an adjoining vertex (lines joining a vertex to an adjoining vertex would simply be a side of the polygon). Since a triangle has only got adjoining vertices, it has no diagonals. Since there are no diagonals, they cannot bisect one another.
One angel will be 15 and the other 75
Yes because it has vertex,faces,and edges just like a cube has. I hoped I answered this right