There are an infinite number of answers ot this question - three consecutive numbers which add to this number are 31 + 32 + 33 = 96
To find the average of a set of numbers:1. sum up the numbers92 + 96 + 94 = 2822. divide the sum by the total number of numbers in the set282 / 3 = 9494 is the average.
90, 94, 96
96+98+100 = 294
31 + 32 + 33 = 96 I'm guessing you meant consecutive numbers.
Let's represent the four consecutive whole numbers as n, n+1, n+2, and n+3. The sum of these numbers can be expressed as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is 96, we can set up the equation 4n + 6 = 96 and solve for n. Subtracting 6 from both sides gives us 4n = 90, and dividing by 4 gives n = 22.5. However, since n must be a whole number, we can see that this is not a valid solution. Therefore, there are no four consecutive whole numbers that sum up to 96.
-67
To find the average of a set of numbers, you add all the numbers together and then divide by the total number of values. In this case, the sum of 96, 100, and 92 is 288. Dividing 288 by 3 (the total number of values) gives an average of 96.
Divide 96 by 3= 32 your three numbers are now: 32 -1 = 31 32 = 32 32 + 1=33 31 + 32 +33 = 96
31, 7, 5
103
You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).
Sorry. No sum of even numbers can be an odd number.