There are an infinite number of sets of 3 numbers which total 13.
13, 1, -1
12, 2, -1
14, 1, -2
100, -50, -37
12, .3, .7
1, 5, 7
2, 6, 5
etc...
1,13,72
If you add 5 + 5 + 5 you get 15. This is the minimum value you can use so there can be no solution. Or the question is faulty.
The next number is 13, the total of the two numbers preceding it.
13+1+6=30Write 9 by turning 180 degThat is 6
1, 3, 5, 7, 9, 11, 13, 15, 17There are a total of 9 odd numbers under 19.
1,13,72
Probability(Total = 7) = 15/216 = 0.069 Probability(Total = 13) = 21/216 = 0.097
If you add 5 + 5 + 5 you get 15. This is the minimum value you can use so there can be no solution. Or the question is faulty.
No whole 3 consecutive numbers total 46.
10 + (-3) = 7 10 - (-3) = 13 10 and -3
The next number is 13, the total of the two numbers preceding it.
13+1+6=30Write 9 by turning 180 degThat is 6
1, 3, 5, 7, 9, 11, 13, 15, 17There are a total of 9 odd numbers under 19.
1 + 1 + 3 + 3 + 5 = 13
The prime numbers less than 30 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29This is a total of ten numbers.
The prime numbers from 1 to 13 are 2, 3, 5, 7, 11, and 13.
2 is an even prime number. 3, 7, 11, 13 are odd prime numbers.