There are an infinite number of sets of 3 numbers which total 13. 13, 1, -1 12, 2, -1 14, 1, -2 100, -50, -37 12, .3, .7 1, 5, 7 2, 6, 5 etc...
3 + 5 + 5
The next number is 13, the total of the two numbers preceding it.
8 and 5 8-5 = 3 8+5 = 13
73
There are an infinite number of sets of 3 numbers which total 13. 13, 1, -1 12, 2, -1 14, 1, -2 100, -50, -37 12, .3, .7 1, 5, 7 2, 6, 5 etc...
1 + 1 + 3 + 3 + 5 = 13
3 + 5 + 5
3 5 7 9 11 13 15 17 19....the sum total of these numbers is100..make it a group of 5-5..so that each group has its sum totAL OF 50.
The next number is 13, the total of the two numbers preceding it.
8 and 5 8-5 = 3 8+5 = 13
8 and 5
73
The prime numbers from 1 to 13 are 2, 3, 5, 7, 11, and 13.
1, 3, 5, 7, 9, 11, 13, 15, 17There are a total of 9 odd numbers under 19.
3, 5 5, 7 11, 13
If you have a list of numbers,5, 12, 15, 13, 3, 6,You add them all together,5+12+15+13+3+6 = 54And divide the sum by the amount of numbers (5, there are 5 numbers in the list)54 ÷ 5 = 10.810.8 is the mean number of 5, 12, 15, 13, 3, and 6