There are an infinite number of sets of 3 numbers which total 13.
13, 1, -1
12, 2, -1
14, 1, -2
100, -50, -37
12, .3, .7
1, 5, 7
2, 6, 5
etc...
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∙ 13y ago1,13,72
If you add 5 + 5 + 5 you get 15. This is the minimum value you can use so there can be no solution. Or the question is faulty.
The next number is 13, the total of the two numbers preceding it.
13+1+6=30Write 9 by turning 180 degThat is 6
1, 3, 5, 7, 9, 11, 13, 15, 17There are a total of 9 odd numbers under 19.
Probability(Total = 7) = 15/216 = 0.069 Probability(Total = 13) = 21/216 = 0.097
No whole 3 consecutive numbers total 46.
10 + (-3) = 7 10 - (-3) = 13 10 and -3
13+1+6=30Write 9 by turning 180 degThat is 6
The next number is 13, the total of the two numbers preceding it.
1 + 1 + 3 + 3 + 5 = 13
The prime numbers less than 30 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29This is a total of ten numbers.
The prime numbers from 1 to 13 are 2, 3, 5, 7, 11, and 13.
The average of these numbers is 12.7You calculate this by adding all the numbers up (which in this case equals 254) and then divide by the total number of numbers (which in this case is 20 numbers) 254 divided by 20 equals 12.7
3 5 7 9 11 13 15 17 19....the sum total of these numbers is100..make it a group of 5-5..so that each group has its sum totAL OF 50.
8 and 5
The prime numbers (factors) of 39 are: 3 and 13