There are an infinite number of sets of 3 numbers which total 13.
13, 1, -1
12, 2, -1
14, 1, -2
100, -50, -37
12, .3, .7
1, 5, 7
2, 6, 5
etc...
1,13,72
To find the total number of combinations using three series of numbers, each ranging from 1 to 13, you multiply the number of choices for each series. Since each series has 13 options, the total combinations are (13 \times 13 \times 13), which equals (13^3 = 2,197). Therefore, there are 2,197 possible combinations.
If you add 5 + 5 + 5 you get 15. This is the minimum value you can use so there can be no solution. Or the question is faulty.
The next number is 13, the total of the two numbers preceding it.
13+1+6=30Write 9 by turning 180 degThat is 6
1,13,72
The product of 13 and 3 is calculated by multiplying the two numbers together. In this case, 13 multiplied by 3 equals 39. Multiplication is a mathematical operation that combines two numbers to find their total value. In this instance, 13 groups of 3 equals 39.
Probability(Total = 7) = 15/216 = 0.069 Probability(Total = 13) = 21/216 = 0.097
To find the total number of combinations using three series of numbers, each ranging from 1 to 13, you multiply the number of choices for each series. Since each series has 13 options, the total combinations are (13 \times 13 \times 13), which equals (13^3 = 2,197). Therefore, there are 2,197 possible combinations.
If you add 5 + 5 + 5 you get 15. This is the minimum value you can use so there can be no solution. Or the question is faulty.
No whole 3 consecutive numbers total 46.
10 + (-3) = 7 10 - (-3) = 13 10 and -3
13+1+6=30Write 9 by turning 180 degThat is 6
The next number is 13, the total of the two numbers preceding it.
1, 3, 5, 7, 9, 11, 13, 15, 17There are a total of 9 odd numbers under 19.
1 + 1 + 3 + 3 + 5 = 13
They are: 3*13 = 39