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The product of 36 (= 9 X 4) by any integer will be integrally divisible by both 4 and 9. The smallest integer by which 36 can be multiplied to yield a product with five digits is 278, for which the product is 10,008. The largest integer by which 36 can be multiplied to yield a product with no more than five digits is 2777, for which the product is 99,972. Therefore, the product of 36 multiplied by any integer from 278 to 2777, inclusive, satisfies the requirements stated in the problem. 36,000 and 46,656 are examples.

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Q: What 5 digit number cam be divisible by 9 and 4?
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