Answer
196, 198, 200, 202, 204
Details
Procedure
Assume the numbers are such that the middle one is 2n,
the assumed numbers are: 2n-4, 2n-2, 2n, 2n+2, 2n+4 ..... (1)
Summation = 10n = 1000
so, n = 100
Substitute with n = 100 in (1) we get the answer above
1019, 1021
Assume that the consecutive numbers are: x, x+1, x+2, x+3 Then: x + x+1 + x+2 + x+3 = 1000 4x + 6 = 1000 4x = 1000 - 6 = 994 x = 248.5 The numbers are: 248.5, 249.5, 250.5, 251.5
31-32
1003
3003
3003
1049 x 1051 = 1102499
Oh, dude, that's an easy one. So, you can write any number less than 1000 as the product of 3 consecutive numbers, right? Well, except for the numbers at the beginning and end because they don't have 3 numbers before or after them to multiply with. So, that leaves us with 997 numbers. Easy peasy lemon squeezy.
5,000 and 3,096
There is an infinite amount of numbers that this applies to. I will define difference for you. Difference is the amount you get when subtracting two numbers. Example 2000 - 1000 has a difference of 1000. same with 2001 and 1001 etc.
do not know i thought i asked that question your fake
The two consecutive numbers that have a digit sum of 27 and 1 are 999 and 1000. explanation: 9+9+9= 27 1+0+0= 1 (does not matter how many zeros you add, it will always equal 1) Next number after 999 is 1000.