3003
Let the three consecutive numbers be ( x ), ( x + 1 ), and ( x + 2 ). Their sum can be expressed as ( x + (x + 1) + (x + 2) = 3x + 3 ). Setting this equal to 3000 gives the equation ( 3x + 3 = 3000 ). Solving for ( x ) yields ( x = 999 ), so the three consecutive numbers are 999, 1000, and 1001.
Yes.
42 = 20 + 22
None exist. 100 is an even number and two consecutive integers can only add up to an odd number. This is because only 2 evens can add up to an even number and no two even numbers are consecutive. (or two odds, but no two odd numbers are consecutive either)
4+5=9
3003
Let the numbers be n, n+1, n+ 2, n+3. Hence n + n+1 + n+ 2 + n+3 = 35 Collect like terms 4n + 6 = 35 Subtract '6' from both sides 4n = 29 Divide both sides by '4' n = 7.25 , 8.25, 9.25, 10.25
The sum of consecutive integers will always be odd. Consecutive odd numbers will be even. 299 + 301 = 600
I am not sure if any two consecutive numbers can add up to an even number.
Answer: The even numbers are 62, 64, 66, and 68
Let the three consecutive numbers be ( x ), ( x + 1 ), and ( x + 2 ). Their sum can be expressed as ( x + (x + 1) + (x + 2) = 3x + 3 ). Setting this equal to 3000 gives the equation ( 3x + 3 = 3000 ). Solving for ( x ) yields ( x = 999 ), so the three consecutive numbers are 999, 1000, and 1001.
42 = 20 + 22
Yes.
28
It is cool rite
None exist. 100 is an even number and two consecutive integers can only add up to an odd number. This is because only 2 evens can add up to an even number and no two even numbers are consecutive. (or two odds, but no two odd numbers are consecutive either)
The sum of 2 consecutive numbers cannot be 118, because you cannot get an even number when you add an even and an odd number.