(6 x 4) + (6 x 5) + (6 x 6) + (6 x 7) + (6 x 8) + (6 x 9) = 234
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
Multiples of 3 include 3, 6, 9, 12, 15 3 and 6 are consecutive. 6 and 9 are consecutive. 9 and 12 are consecutive and so on.
18, 15, 12, 9, 6, 3
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
2, 3, 4, 5 and 6 are multiples of 2, 3, 4, 5 and 6.
The common multiples of 6 and 13 are the infinite set of multiples of their LCM, which is 78. So the common multiples of 6 and 13 are 78, 156, 234, 312, 390, and so on.
Factors: 1, 2, 3, 6, 13, 26, 39, 78 Multiples: 78, 156, 234 and so on.
234 / 12 = 19 feet 6 inches
The multiples of 6 are: 6x1 and 2x3.
The LCM of two consecutive numbers is their product. The LCM of two consecutive multiples of 5 is their product divided by 5. Two consecutive numbers cannot be multiples of 5.
Let "a" be the first of the four numbers. Then we are told:a + (a + 1) + (a + 2) + (a + 3) = 234∴ 4a + 6 = 234∴ 4a = 228∴ a = 57So the numbers are 57, 58, 59 and 60
i think 234