Let the second of the three consecutive multiples of 6 be 6n
Then the first is 6n - 6 and the last is 6n + 6;
and:
(6n - 6) + 6n + (6n + 6) = 666
→ 18n = 666
→ n = 37
→ the consecutive multiples of 6 which sum to 666 are 216, 222, 228
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Let the 1st multiple of 6 be x
Let the 2nd multiple be x+6
Let the 3rd multiple be x+6+6=x+12
According To question
x+x+6+x+12=666
3x+18=666
x=216
x+6=222
x+12=228
So the multiples are 216,222,228