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Let the second of the three consecutive multiples of 6 be 6n

Then the first is 6n - 6 and the last is 6n + 6;

and:

(6n - 6) + 6n + (6n + 6) = 666

→ 18n = 666

→ n = 37

→ the consecutive multiples of 6 which sum to 666 are 216, 222, 228

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8y ago

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More answers

Let the 1st multiple of 6 be x

Let the 2nd multiple be x+6

Let the 3rd multiple be x+6+6=x+12

According To question

x+x+6+x+12=666

3x+18=666

x=216

x+6=222

x+12=228

So the multiples are 216,222,228

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Didar Singh

Lvl 2
3y ago
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The sum of three consecutive number 6666 find the multiples

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Anonymous

4y ago
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Q: The sum three consecutive multiples of 6 is 666 find these multiples?
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