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Let the second of the three consecutive multiples of 6 be 6n

Then the first is 6n - 6 and the last is 6n + 6;

and:

(6n - 6) + 6n + (6n + 6) = 666

→ 18n = 666

→ n = 37

→ the consecutive multiples of 6 which sum to 666 are 216, 222, 228

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8y ago

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