None.
Sum of numbers = 40 Count of numbers = 4 Average = Sum/Count = 40/4 = 10
In total, we are changing the sum of the 9 numbers by 1 + 2 + ... + 9 = 9 x 10 / 2 = 45, so each of the numbers is increased by, on average, 45/9=5. If the old average was 40, the new one is 40 + <the average amount each number was increased by> = 40 + 5 = 45.
6 + 10 + 8 + 7 + 9= 40----------you have 5 integers, so......40/5= 8=====the arithmetic average, or the mean of these numbers
40 ÷ 5 = 8, so the average of the five numbers will be 8. That means that 8 will be in the middle. 6 + 7 + 8 + 9 + 10 = 40
9 out of 40 is 9/40. There is nothing to average! 9/40 = 0.225
9 and -40 9 + -40 = -31 9 x -40 = -360
The average of five numbers whose sum is 200 will always be 40, no matter which numbers you choose. When finding an average, you add up the numbers (find the sum of the set), then divide by the number of terms. In this case, the sum will always be 200, and there will always be five terms. This will always result in an average of 40. Ex/ 1 + 2 + 3 + 4 + 190 = 200 200 / 5 = 40 40 + 40 + 80 + 24 + 16 = 200 200 / 5 = 40
The average of 31,52and 40 is 41 because you add all the numbers and then didvde it by 3 because there are 3 numbers there and you get 41.
45
Mean refers to average. To get an average you add up all the numbers in your set. Here, your set is 6, 7, 8, 9 and 10 ( I have arranged them in numerical order). You also need to know the number of numbers in your set. Here, you have five numbers in your set. I will call the number of numbers in the set n, and thus n = 5 here. Once you have the sum of all the numbers, divide by n. Here, the sum is 40 (6 + 7 + 8 + 9 + 10). Now divide by n. 40/5 = 8. Thus the average, or MEAN is 8.
40 and 9
The average of a series of numbers is their sum divided by however many numbers there are: in this case you would calculate: (16 + 40) / 2 =56 / 2 =28 Therefore the average of 16 and 40 is 28.