40 ÷ 5 = 8, so the average of the five numbers will be 8. That means that 8 will be in the middle.
6 + 7 + 8 + 9 + 10 = 40
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The numbers are 73, 74, 75, 76 and 77.
To find three numbers that multiply together to equal 40, we need to consider the prime factors of 40, which are 2, 2, 2, and 5. We can group these prime factors into three numbers: 2, 2, and 10. Therefore, the three numbers that multiply to 40 are 2, 2, and 10.
Assuming you mean which 5 consecutive numbers added give a total of 45... One answer would be 7,8,9,10 & 11
After (3, 5, 7), you can't have any more such "triplets", since one of the three must needs be a multiple of 3.
There are no whole numbers between 5 and 6 because they are consecutive to one another in the number series.