41
a 3 digit number that is divisible by on is a three digit number that is a multiple of one.
It is a 4 digit multiple of 6.
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
There is no number that is "divisible by 4" and "not divisible by 4" at the same time - a number cannot be both a multiple of 4 and not a multiple of 4.
The greatest 4-digit number that is divisible by 16 is 9984
99968
Oh, what a delightful little puzzle we have here! To find a four-digit number that is divisible by both 8 and 9, we can look for a number that is divisible by their least common multiple, which is 72. So, let's find a multiple of 72 that is a four-digit number, like 1008. Such a harmonious number, don't you think?
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.
11
The number is 24.
To find a 4-digit number that is divisible by both 8 and 9, we need to find a number that is a multiple of the least common multiple of 8 and 9, which is 72. Starting from the smallest 4-digit multiple of 72, which is 1008, we can find the next number by adding 72 until we reach a 4-digit number. Therefore, the smallest 4-digit number that is divisible by both 8 and 9 is 1008.
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.