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The numbers are 55, and 57.

Two consecutive integers have an odd sum.

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0Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.

It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.

Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.

There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.

The integers are -2, 0, 2 and 4.

There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.

-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.

Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.

The numbers are 37 and 39.

The numbers are 125 and 126.

The integers are -2, -1, 0 and 1.

Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.

The numbers are -53 and -52.

The numbers are -53 and -52.

The numbers are -53 and -52.

114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114

No.Let the four numbers be (n-1), n, (n+1), (n+2).Their sum is 4n + 2 = 2(2n + 1)If 2000 is the sum of four consecutive integers, then:2(2n+1) = 2000⇒ 2n + 1 = 1000⇒ 2n = 999but 999 is odd, not even and so n cannot be an integer; therefore 2000 is not the sum of four consecutive integers.

The numbers are -2, -1, 0, 1 and 2.

29 cannot be the sum of two odd integers. The sum of two odd integers is always an even integer.

Since 16 + 25=41, we know the integers are 4 and 5.

No two consecutive EVEN integers sum to 124 since: Let x be the lowest of the two integers. Then the other integer is x+2 and x + (x+2) = 124 iff 2x = 122 iff x=61, an odd integer.

The pair of consecutive integers which add up to 55 are 27 and 28. Therefore, any consecutive pair of numbers below 27 and 28 add up to a total less than 55.

The integers are -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5. The largest is five.

112/4 = 28 so two odd numbers before 28 and two after. 25 + 27 + 29 + 31 = 112 so 31 is the greatest.

No, they are consecutive but sum means that if you add them together it will equal 36. Also 2 is not odd. The numbers you are looking for are 17 and 19.

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