Best Answer

Suppose the three numbers are x-1, x and x+1

then (x-1)*x + 28 = (x+1)2

or x2 - x + 28 = x2 + 2x + 1

or 3x = 27 so that x = 9 and the three numbers are 8, 9 and 10.

Q: What are 3 consecutive numbers when the product of the smallest two numbers is 28 less than the square of the largest number?

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There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.

The largest number is 9.

2 x 47 = 94

There is no set of four consecutive numbers with a product of 182. There is a set of four consecutive numbers with a sumof 182: 9, 20, 21 and 22.

12, 13 and 14

Related questions

There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.

Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

The largest number is 9.

Yes.

5,6,7

11,12,13

2 x 47 = 94

2 x 47 = 94

8,10,12

The GCF of two consecutive numbers is always 1. The GCF of any set of numbers can't be greater than the smallest of the differences between the numbers.

There is no set of four consecutive numbers with a product of 182. There is a set of four consecutive numbers with a sumof 182: 9, 20, 21 and 22.

1, 3, 5