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Suppose the three numbers are x-1, x and x+1

then (x-1)*x + 28 = (x+1)2

or x2 - x + 28 = x2 + 2x + 1

or 3x = 27 so that x = 9 and the three numbers are 8, 9 and 10.

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Q: What are 3 consecutive numbers when the product of the smallest two numbers is 28 less than the square of the largest number?
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