They are 2,3 and 5
The product of the first three prime numbers (2, 3, and 5) is 30.
2*3*19
Their product is: 3*5*7*9*11*13*15*17*19 = 654,729,075
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
How about: 2*3*5 = 30 which is the product of the 1st three prime numbers
16 and 3
5 * 2 * 3
How about: 2*3*5 = 30 as a product of its prime factors
30 is the product of three different prime numbers.
19 doesn't belong. The rest of the numbers are multiples of 3.
30 cannot be written as the product of 6 prime numbers. 30 has three prime factors: 2 x 3 x 5 = 30
Two, three, and five have a product of thirty (2*3*5).