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Let the first even number be x. Then the second even number would be x + 2, and the third even number would be x + 4. The sum of these numbers is x + (x + 2) + (x + 4) = 3x + 6. We set this equal to 204 and solve for x: 3x + 6 = 204 --> 3x = 198 --> x = 66. Therefore, the three consecutive even numbers are 66, 68, and 70.

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66

68

70

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204

Q: What are Three consecutive even numbers add to 204?

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"Consecutive integers of -204" doesn't really make sense; -204 is just a single integer.

The three are 204/3 - 1, 204/3 and 204/3 + 1 ie 67, 68 and 69

207

2 + 3 + 199 = 204

200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11

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The three numbers will have a mean of 204/3 = 68. The two numbers are therefore 66, 68, 70.

"Consecutive integers of -204" doesn't really make sense; -204 is just a single integer.

The three are 204/3 - 1, 204/3 and 204/3 + 1 ie 67, 68 and 69

There is no set of four consecutive odd integers for 204. The only set is even: 48, 50, 52 and 54.

207

2 + 3 + 199 = 204

Here's how you can work it out: First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say: x + (x + 2) + (x + 4) = 210 ∴ 3x + 6 = 210 ∴ 3x = 204 ∴ x = 68 We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together: 68 + 70 + 72 = 210 which confirms our answer.

-15 and -14 or 14 and 15 <><><><><> Or, if you consider whole numbers to be positive integers, then just 14 and 15.

200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11

132, 156 and 204

The prime factors of 204 are: 2 3 17

They are: 2+5+11+89+97 = 204