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Here's how you can work it out:

First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say:

x + (x + 2) + (x + 4) = 210

∴ 3x + 6 = 210

∴ 3x = 204

∴ x = 68

We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together:

68 + 70 + 72 = 210

which confirms our answer.

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2010-04-10 17:32:49
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Q: What are 3 consecutive even integers whose sum is 210?
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What is three consecutive even integers whose sum equals 210?

Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72


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