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Here's how you can work it out:
First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say:
x + (x + 2) + (x + 4) = 210
∴ 3x + 6 = 210
∴ 3x = 204
∴ x = 68
We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together:
68 + 70 + 72 = 210
which confirms our answer.
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How do you work out the 2 consecutive numbers that make 702 and 210?
You cannot.If you have any two consecutive numbers, one of them must be odd and the other even. So their sum must be odd and therefore cannot be 702 nor 210
How can you solve the problem finding two consecutive positive integers whose product is 210?
Let x = first positive integer the x + 1 is the next positive integer the product is x (x+1) = 210 x^2 + x = 210 x^2 + x - 210 = 0 Use quadratic equation to solve, or factor (X+15) (X-14 ) = 0 x = +14 or X = -15 The positve one is x = 14 X + 1 = 15 ANS: 14 and 15
Could somebody help me with math A positive integer is said to be trifactorable if it is the product of three consecutive integers How many positive integers less than 1000 are trifactorable?
1x2x3=6 2x3x4=24 3x4x5=60 4x5x6=120 5x6x7=210 6x7x8=336 7x8x9=504 8x9x10=720 9x10x11=990
What are four consecutive numbers that add up to 210?
The numbers are 51, 52, 53 and 54.
Lcm of two consecutive numbers is greater than 200 and is a multiple of 7?
To find the least common multiple (LCM) of two consecutive numbers that is greater than 200 and is a multiple of 7, we need to consider the properties of consecutive numbers and multiples of 7. Since the LCM must be greater than 200 and a multiple of 7, the two consecutive numbers must be 28 and 29. The LCM of 28 and 29 is 812, which is greater than 200 and a multiple of 7.
What is three consecutive even integers whose sum equals 210?
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
The product of two consecutive integers is 210?
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
What are the sum of consecutive integers of 1060?
210, 211, 212, 213 and 214.
What would be three times the largest of three consecutive even integers is seventy six more than the sum of the other two integers?
66, 68, 70 Check: 66+68=134, 134+76=210, 210/3=70 ; 66, 68, 70
How many pairs of prime numbers are there which are consecutive odd integers?
There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.
Product of three concecutive integer is 210 then find the sum of smallest two integers?
Let's assume that the three consecutive integers are n-1, n, and n+1. We know that their product is 210, so we can set up the equation (n-1)(n)(n+1) = 210. By solving this equation, we can find that the three integers are 6, 7, and 8. Therefore, the sum of the smallest two integers is 6 + 7 = 13.
How do you work out the 2 consecutive numbers that make 702 and 210?
You cannot.If you have any two consecutive numbers, one of them must be odd and the other even. So their sum must be odd and therefore cannot be 702 nor 210
The product of three consecutive integers is 210 What is the least of these integers?
The Answer:This, we can notate as: (x - 1)x(x + 1) = (x2 - 1)x = x3 - x = 210.x3 - x - 210 = (x - 6)(x2 + 6x + 35) = 0Thus, 6 = x (or -3 +- i*sqrt(26)). The real solution, 6, can be plugged back into x - 1 (the lowest), producing 5. 5 is your answer.
What three consecutive numbers have a product of 210?
5*6*7 = 210
How you will get 210 by mulitiplying 2 consecutive numbers?
14 x 15 = 210
How can you solve the problem finding two consecutive positive integers whose product is 210?
Let x = first positive integer the x + 1 is the next positive integer the product is x (x+1) = 210 x^2 + x = 210 x^2 + x - 210 = 0 Use quadratic equation to solve, or factor (X+15) (X-14 ) = 0 x = +14 or X = -15 The positve one is x = 14 X + 1 = 15 ANS: 14 and 15
How do you calculate the least common multiple of 2 consecutive numbers that is greater than 200 and a multiple of 7?
Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.
