0
Here's how you can work it out:
First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say:
x + (x + 2) + (x + 4) = 210
∴ 3x + 6 = 210
∴ 3x = 204
∴ x = 68
We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together:
68 + 70 + 72 = 210
which confirms our answer.
Still curious? Ask our experts.
Chat with our AI personalities
Beau
Taiga
JordanAdd your answer:
Earn +20 pts
How do you work out the 2 consecutive numbers that make 702 and 210?
You cannot.If you have any two consecutive numbers, one of them must be odd and the other even. So their sum must be odd and therefore cannot be 702 nor 210
How can you solve the problem finding two consecutive positive integers whose product is 210?
Let x = first positive integer the x + 1 is the next positive integer the product is x (x+1) = 210 x^2 + x = 210 x^2 + x - 210 = 0 Use quadratic equation to solve, or factor (X+15) (X-14 ) = 0 x = +14 or X = -15 The positve one is x = 14 X + 1 = 15 ANS: 14 and 15
Could somebody help me with math A positive integer is said to be trifactorable if it is the product of three consecutive integers How many positive integers less than 1000 are trifactorable?
1x2x3=6 2x3x4=24 3x4x5=60 4x5x6=120 5x6x7=210 6x7x8=336 7x8x9=504 8x9x10=720 9x10x11=990
What are four consecutive numbers that add up to 210?
The numbers are 51, 52, 53 and 54.
Lcm of two consecutive numbers is greater than 200 and is a multiple of 7?
To find the least common multiple (LCM) of two consecutive numbers that is greater than 200 and is a multiple of 7, we need to consider the properties of consecutive numbers and multiples of 7. Since the LCM must be greater than 200 and a multiple of 7, the two consecutive numbers must be 28 and 29. The LCM of 28 and 29 is 812, which is greater than 200 and a multiple of 7.
