66
68
70
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204
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Let the first even number be x. Then the second even number would be x + 2, and the third even number would be x + 4. The sum of these numbers is x + (x + 2) + (x + 4) = 3x + 6. We set this equal to 204 and solve for x: 3x + 6 = 204 --> 3x = 198 --> x = 66. Therefore, the three consecutive even numbers are 66, 68, and 70.
"Consecutive integers of -204" doesn't really make sense; -204 is just a single integer.
The three are 204/3 - 1, 204/3 and 204/3 + 1 ie 67, 68 and 69
207
2 + 3 + 199 = 204
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11