They are 1, 2, 3, 4, 6, 7, 8, 12, 24.
There are no factors in the normal sense of the term "factor", but ... Suppose a and b are the factors. Then a+b=7 so that b = 7-a Also a*b = -24 so that a*(7-a) = -24 ie a2 - 7a - 24 = 0 The roots of this quadratic are 1/2*[7 +/- sqrt(72 + 4*1*24)] = 1/2*[7 +/- sqrt(145)] which gives the two factors given above. 3 and 4 are factors of -24. 1 and 6 are factors of -24.
Yes, all the factors of 12 are factors of 24.
7 - 1, 7 24 - 1, 2, 3, 4, 6, 8, 12, 24
To find the common factors of 14 and 98, we first list the factors of each number. The factors of 14 are 1, 2, 7, and 14, while the factors of 98 are 1, 2, 7, 14, 49, and 98. The common factors are 1, 2, 7, and 14. To find the sum of these common factors, we add them together: 1 + 2 + 7 + 14 = 24.
The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24 The factors of 35 are: 1, 5, 7, 35
All Factors of 9: 1, 3, 9.All Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24.
Prime factors of 48: 24 and 3 Prime factors of 84: 22, 3 and 7 LCM by multiplying the highest prime factors: 24*3*7 = 336
the factors of 7 are 1 and 7
Seven factors.
The factors of 14 are: 1, 2, 7, 14 The factors of 20 are: 1, 2, 4, 5, 10, 20
The even factors of 24 are the factors that are divisible by 2. They are 2, 4, 6, 8, 12, and 24. These numbers divide 24 without leaving a remainder and are all even.
The factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24