The prime factors of 180 are 2, 3, and 5 .
No. The Prime Factors of 180 are: 2, 3, 5.
The prime factors are: 2,3,5
The prime factors of 180 are the prime numbers that can be multiplied together to equal 180. To find the prime factors of 180, we start by dividing 180 by the smallest prime number, which is 2. Continuing this process, we find that the prime factors of 180 are 2, 2, 3, 3, and 5, represented as 2^2 * 3^2 * 5.
As a product of its prime factors: 2*2*3*3*5 = 180
2,3,5
To work out the prime factors of 180 in index form, you first need to find the prime factors of 180. Start by dividing 180 by the smallest prime number, which is 2. Continue dividing by prime numbers until you cannot divide any further. The prime factors of 180 are 2, 2, 3, 3, and 5. In index form, this would be written as 2^2 * 3^2 * 5.
prime factors of 180:(180) = 2 * (90)(90) = 2 * (45)(45) = 3 * (15)(15) = 3 * 5prime factors of 180 are: 2*2*3*3*5
As a product of its prime factors in exponents: 22*32*5 = 180 So 5 is its largest prime factor.
2, 3 and 5
As a product of its prime factors: 2*2*3*3*5 = 180
Done correctly, all factor trees for 180 will be the same size. Since 180 has five prime factors, there will be five branches. 180 90,2 45,2,2 15,3,2,2 5,3,3,2,2