The prime factors of 180 are 2, 3, and 5 .
No. The Prime Factors of 180 are: 2, 3, 5.
The prime factors are: 2,3,5
As a product of its prime factors: 2*2*3*3*5 = 180
2,3,5
To work out the prime factors of 180 in index form, you first need to find the prime factors of 180. Start by dividing 180 by the smallest prime number, which is 2. Continue dividing by prime numbers until you cannot divide any further. The prime factors of 180 are 2, 2, 3, 3, and 5. In index form, this would be written as 2^2 * 3^2 * 5.
prime factors of 180:(180) = 2 * (90)(90) = 2 * (45)(45) = 3 * (15)(15) = 3 * 5prime factors of 180 are: 2*2*3*3*5
As a product of its prime factors in exponents: 22*32*5 = 180 So 5 is its largest prime factor.
2, 3 and 5
As a product of its prime factors: 2*2*3*3*5 = 180
The prime factorization of 2x2x3x3x5 is 2^2 * 3^2 * 5. When we multiply these prime factors together, we get the number 180. Therefore, the number with the prime factorization of 2x2x3x3x5 is 180.
Done correctly, all factor trees for 180 will be the same size. Since 180 has five prime factors, there will be five branches. 180 90,2 45,2,2 15,3,2,2 5,3,3,2,2