The prime factors are: 2, 3, 5 2, 3 and 52 x 2 x 3 x 3 x 5 = 1802, 3 and 5
The factors of 540 are: 1 2 3 4 5 6 9 10 12 15 18 20 27 30 36 45 54 60 90 108 135 180 270 540. The prime factors are: 2, 3 and 5
The prime factors are 2x2x2x13 All factors are 1,104,2,52,4,26,8,13
the answer is ........ factors are 1,2,3,6,9,18 ; 1x18,2x9,3x6 prime factors are 2x3x3
Oh, dude, the "HCF" stands for the Highest Common Factor, which is like the biggest number that can divide both 135 and 180 without leaving a remainder. So, if we break it down, the prime factors of 135 are 3 x 3 x 3 x 5, and the prime factors of 180 are 2 x 2 x 3 x 3 x 5. The HCF is the product of the common prime factors with the lowest powers, which in this case is 3 x 3 x 5, which equals 45.
No. The Prime Factors of 180 are: 2, 3, 5.
The prime factors of 180 are 2, 3, and 5 .
As a product of its prime factors: 2*2*3*3*5 = 180
2,3,5
To work out the prime factors of 180 in index form, you first need to find the prime factors of 180. Start by dividing 180 by the smallest prime number, which is 2. Continue dividing by prime numbers until you cannot divide any further. The prime factors of 180 are 2, 2, 3, 3, and 5. In index form, this would be written as 2^2 * 3^2 * 5.
prime factors of 180:(180) = 2 * (90)(90) = 2 * (45)(45) = 3 * (15)(15) = 3 * 5prime factors of 180 are: 2*2*3*3*5
As a product of its prime factors in exponents: 22*32*5 = 180 So 5 is its largest prime factor.
2, 3 and 5
2, 3 and 5
As a product of its prime factors: 2*2*3*3*5 = 180
The prime factorization of 2x2x3x3x5 is 2^2 * 3^2 * 5. When we multiply these prime factors together, we get the number 180. Therefore, the number with the prime factorization of 2x2x3x3x5 is 180.
As a product of its prime factors: 2*2*3*3*5 = 180