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What are all the two digit numbers that are divisible by both the sum and the product of its digits?
Wiki User
∙ 14y ago
There are three such numbers: 12, 24 and 36.
Wiki User
∙ 14y ago
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How many 3-d How many 3-digit numbers will be there which are divisible by 19igit numbers with atleast one 5 in their digits?
None. 3 digit numbers are not divisible by 19 digit numbers.
You are a 3 digit multiple of 10 you are the product of two consecutive numbers you are divisible by 6 and 7 the sum of your digits is 6 what is your number?
420
What is the smallest two digit number that is divisible by both the sum and the product of its digits?
12
What are the divisibility rules for 1 2 3 4 5 6 9 and 10?
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
Find 5 four digit numbers such that the product of the digits of each four digit prime number are also prime?
You had me until "product." The product of 4 digits can't be prime.
List all of the two digit numbers that are divisible by the product of their digits?
There are five such numbers: 11, 12, 15, 24 and 36.
How many 3-d How many 3-digit numbers will be there which are divisible by 19igit numbers with atleast one 5 in their digits?
None. 3 digit numbers are not divisible by 19 digit numbers.
You are a 3 digit multiple of 10 you are the product of two consecutive numbers you are divisible by 6 and 7 the sum of your digits is 6 what is your number?
420
The two digit number that is divisible by the sum and the product of its digits?
12 or 24
How many 2-digit or 3-digit numbers can be formed using the digits 134568 and 9 which are diisible by 4?
48. Assuming no digit can be used more than once, the two digit numbers divisible by 4 are: 16, 36, 48, 56, 64, 68, 84, 96 8 of them. For any number to be divisible by 4, only the last two digits need be divisible by 4; so for three digit numbers, each of the two digit numbers above can be preceded by any of the remaining 5 digits and still be divisible by 4. → 5 x 8 = 40 three digit numbers are divisible by 4 → 40 + 8 = 48 two or three digit numbers made up of the digits {1, 3, 4, 5, 6, 8, 9} are divisible by 4. If repeats are allowed, there are an extra 2 two digit numbers (44 and 88) and each of the two digit numbers can be preceded by any of the 7 digits, making a total of 7 x 10 + 10 = 80 two and three digits numbers divisible by 4 make up of digits from the given set.
How many 6 digits numbers can be formed from the digit 01357 and 9 which are divisible by 10 and no digit is repeated?
There are 5! = 120 such numbers.
What is a two-digit number divisible by 11 and the product of whose digits is 25?
55.
What is the smallest two digit number that is divisible by both the sum and the product of its digits?
12
How many six digit numbers are there in which no digit is repeated even digits appeared in the even places and odd digits in the odd places and the number is divisible by 4?
There are 5760 such numbers.
What are the divisibility rules for 1 2 3 4 5 6 9 and 10?
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
How many digits can the product of 2-digit numbers have?
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
Find 5 four digit numbers such that the product of the digits of each four digit prime number are also prime?
You had me until "product." The product of 4 digits can't be prime.
