Q: How many 6 digits numbers can be formed from the digit 01357 and 9 which are divisible by 10 and no digit is repeated?

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1 set

6*6*3 = 108 numbers.

6*5*4*3*2*1=720 possible numbers

48 of them if digits may not be repeated. 100 if they can.

Whole numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4. For example, the number formed by the last two digits of the number 2628 is 28, which is evenly divisible by 4 so the number 2628 is evenly divisible by 4.

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192 ways

numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4

24

500

There are 5*4*3 = 60 such numbers.

1 set

It is 120 if the digits cannot be repeated.

There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.

3x3x3=27

36

6*6*3 = 108 numbers.

4*3*2*1 = 24