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How many digits will be there in a product of a 4 digit multiplcand and one digit multiplier?
The product of a 4-digit multiplicand and a 1-digit multiplier can have either 4 or 5 digits. If the 4-digit number is multiplied by a multiplier of 1 to 9, the product will typically have 4 digits. However, if the multiplicand is multiplied by 10 (the maximum value for a 1-digit number), the product can reach a maximum of 5 digits. Thus, the product can range from 4 to 5 digits, depending on the specific numbers involved.
What is the greatest number of digits a product could have if a 4-digit number is multiplied by a 2-digit number?
2
Why do the products of multi digit numbers with zeros and one digit numbers sometimes have n zeros and sometimes they have no zeros?
The number of zeros in the product of multi-digit numbers with zeros and one-digit numbers depends on the placement of the zeros in the multi-digit numbers. If a zero is at the end of a multi-digit number, it effectively multiplies the other digits by ten, contributing to the count of zeros in the product. However, if the zeros are located elsewhere, they may not affect the overall count of zeros in the final product. Thus, the final count of zeros can vary based on the specific arrangement of digits.
When you multiply a 3 digit number by a 2 digit number what is the greatest number of digits the product can have?
It can have up to 5 digits.
How many digits can the product of two 2-digits numbers have?
It can have one . . . 1.0 x 1.0 = 1 It can have two . . . 1.0 x 0.1 = 0.1 It can have three . . . 10 x 10 = 100 It can have four . . . 99 x 99 = 9801 and .01 x .01 = .0001
How many digits can the product of 2-digit numbers have?
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
What is the greatest number of digits a product could have if a 4-digit number is multiplied by a 2-digit number?
2
If the sum of a two digit number is 12 and the digits interchange their places the new number exceeds the original number by 25 what is the product?
-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)
What is the last but one digit in the product of the first 75 even natural numbers?
To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
When you multiply a 3 digit number by a 2 digit number what is the greatest number of digits the product can have?
It can have up to 5 digits.
What four 3-digit prime numbers less than 200 each have a prime number for the sum of their digits AND a prime number for the product of their digits?
The four numbers are: 113, 131, 151 and 191. For the product of the digits to be prime, the number must contain 2 ones - which greatly simplifies the exercise.
How many digits can the product of two 2-digits numbers have?
It can have one . . . 1.0 x 1.0 = 1 It can have two . . . 1.0 x 0.1 = 0.1 It can have three . . . 10 x 10 = 100 It can have four . . . 99 x 99 = 9801 and .01 x .01 = .0001
What is the largest two-digit number that is prime and has prime numbers for both of its digits?
73 is the largest two-digit number that is prime and has prime numbers for both of its digits.
How many digits can be the product of two digit numbers have to give examples to support your answer?
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
What is the greatest number of digits a product could have if a 4 digit number is multiplied by a 2 digit number?
Six.
What is a square number a 2 digit number and the product of its digits is 8?
81
What is the total number of digits in the numbers from 1 to 1000000?
In the numbers 1-9 each number has 1 digit and there are 9 of them, so that's 9.In 10-99 each number has 2 digits, and there are 90 of them: 2x90 = 180There are 900 three digit numbers [100 through 999]: 2700 digits.There are 9000 four digit numbers: 36000 digits.90,000 numbers with five digits: 450,000 digits.900,000 numbers with six digits: 5,400,000 digits.Then 1 number with seven digits: 7 digits.Add them up and you have 5,888,896 digits.
