50=
=2*5*5
=1+7*7
=2+2*2*2*2*3
=2+16*3
=2+8*6
=2+4*12
=5+3*3*5
=5+3*15
=5+9*5
=6+2*2*11
=6+4*11
=8+2*3*7
=8+6*7
=8+14*3
=10+2*2*2*5
=10+2*20
=10+4*10
=10+8*5
=11+3*13
=12+2*19
=14+2*2*3*3
=14+2*18
=14+4*9
=14+6*6
=15+7*5
=16*17*2
=17*3*11
=18+2*2*2*2*2
=18+4*8
=18+2*16
=20+2*3*5
=20+6*5
=20+15*2
=2*11+2*2*7
=2*11+4*7
=2*11+2*14
=2*12+2*13
=5*5+5*5
=2*13+2*2*2*3
...
there are many MANY more
120
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
Five numbers can be arranged in 5! = 120 ways.
120
60x20=120 30x40=120
If you're limited to only 5 digits that can't be repeated, then there are 120 ways they can be arranged.
There are 26 different letters.There are 10 different numbers.If a letter or number is allowed to repeat in the code:Number of ways to make 3 letters = 26 x 26 x 26 = 17,576Number of ways to make 2 numbers = 10 x 10 = 100Number of ways to make 3 letters and 2 numbers = 17,576 x 100 = 1,757,600Each group of 3 letters and 2 numbers can be arranged in (5 x 4 x 3 x 2) = 120 different ways.So the number of different codes = 1,757,600 x 120 = 210,912,000 .If a letter or number is not allowed to repeat in the code:Number of ways to make 3 letters = 26 x 25 x 24 = 15,600Number of ways to make 2 numbers = 10 x 9 = 90Number of ways to make 3 letters and 2 numbers = 15,600 x 90 = 1,404,000Each group of 3 letters and 2 numbers can be arranged in (5 x 4 x 3 x 2) = 120 different ways.So the number of different codes = 1,404,000 x 120 = 168,480,000 .
Find out yourself
120 ways.120 ways.120 ways.120 ways.
The number of ways you can arrange the numbers 1 to 5 is calculated using the concept of permutations. There are 5 numbers to arrange, so the total number of arrangements is 5 factorial, denoted as 5!. Therefore, the number of ways to arrange the numbers 1 to 5 is 5! = 5 x 4 x 3 x 2 x 1 = 120 ways.
120 if numbers can start with 0, otherwise, 96.
120 different ways.