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Let the first of the four consecutive integers be represented by n, then the other three can be (n + 1), (n + 2) and (n + 3)

Then we have, n + (n + 1) + (n + 2) + (n + 3) = -142

which simplifies to, 4n + 6 = -142

so, 4n = -142 - 6 = -148........n = -148/4 = -37

The four integers are thus, -37, -36 (-37 + 1), -35 (-37 + 2) and -34 (-37 + 3)

and we have, -37 +(-36) + (-35) + (-34) = -142

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โˆ™ 2011-09-30 19:34:53
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Q: What are four consecutive integers with the sum of -142?
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