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Q: What are four consecutive integers with the sum of -66?

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65, 66, 67

Two possible interpretations of this question. Let the 3 consecutive odd numbers be a, a + 2 and a + 4. 1) a + (a + 4) = [3 x (a + 2)] - 11 2a + 4 = 3a + 6 - 11 : a = 9 The 3 numbers are 9,11 & 13 This gives 9 + 13 = 22 and (3 x 11) - 11 = 22. 2) a + (a + 4) = 3 x (a + 2 -11) 2a + 4 = 3a - 27 : a = 31 The 3 numbers are 31, 33 & 35 This gives 31 + 35 = 66 and 3 x (33 -11) = 3 x 22 = 66.

66 inches is 66 inches.

No, 66 can be divided by 2, 3, 6, 11, 22, 33, 66

Psalm 66 is written by David.

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The numbers are -18, -17, -16 and -15.

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The numbers are -23, -22, and -21.

The average of three numbers which sum to 66 is 66/3 = 22. If 22 is the sum of three consecutive integers, then those three integers are 21,22,23. Kermit Rose

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65, 66, 67

The numbers are 21, 22 and 23.

It's an imaginary number, one that exists only in fiction, if the author wants it to. There are no two consecutive integers whose sum is 66. 32 + 33 = 65 33 + 34 = 67 The sum of two consecutive integers is always an odd number.

66

-66 and -68

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