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Q: The sum of four consecutive integers is 62 what are the four integers?

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They are are 62, 63 and 64.

58, 60, 62, 64

The two even consecutive integers are: 62+64 = 126

There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.

Integers are x, x + 2 and x + 4. This means that 3x + 6 = 192 so 3x = 186, making x = 62, the other integers being 64 and 66.

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They are are 62, 63 and 64.

58, 60, 62, 64

The two even consecutive integers are: 62+64 = 126

The numbers are 62 and 64.

There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.

The numbers are 60, 62, 64, 66 and 68.

The numbers are 62 and 64 are two consecutive integers that equal 126.

61 & 62

Integers are x, x + 2 and x + 4. This means that 3x + 6 = 192 so 3x = 186, making x = 62, the other integers being 64 and 66.

The second integer is 64 (128/2), so the first is 62 and the third is 66.OrLet the 1st integer be x and the 3rd integer be y.Since even integers differ by 2, then we have:y = x + 4x + y = 128x + x + 4 = 1282x = 124x = 62So the integers are 62, 64, and 66, and their sum is 192

Call the lowest of the even integers n. Then from the problem statement, n + n + 2 + n + 4 = n + 6 =244. Collecting like terms results in 4n + 12 = 244, or 4n = 244 - 12 = 232, or n = 232/4 or 58. The consecutive even integers are therefore, 58, 60, 62, and 64.

62 & 61

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