288 is divisible by 2 because it's even.
288 is divisible by 3 because the sum of its digits is a multiple of 3.
288 is divisible by 4 because the last two numbers are divisible by 4.
288 is divisible by 9 because the sum of its digits is a multiple of 9.
A number is a multiple of 312 if it's a multiple of 3, 8 and 13 at the same time
1, 2, 3 and 4
1, 2, 4 and 47
The least 4 factors of 144 are 1, 2, 3, and 4 .
Yes, 104 is a multiple of four. You can tell by using the divisibility rules : if the last two digits of a number are divisible by four, then the whole number is divisible by four. Now lets go back, in case you don't know, divisibility is simply if a smaller number, like four, can go into a larger number, like 104, perfectly;without having to use decimals.
Using the divisibility rules for the numbers 2,3,4,5,6,9, and 10, four hundred seventy is divisible by: 2, 5, and 10
Just knowing the divisibility rules for the first four prime factors (2, 3, 5 and 7) will help find the prime factorizations of a large percentage of the numbers you will encounter. At the very least, dividing your original number by those factors should cut it down to a manageable size. The first thing you do when starting a prime factorization is notice whether the number is even. If it is, you can take out two as a factor. If not, you can skip over it. The same with 3 and 5. If you know they are not factors just by looking at the number, it saves a lot of trial and error.
1, because everything is divisible by 1. 2, because it's even. 3, because the sum of the digits is a multiple of 3. 4, because the last two numbers are a multiple of 4.
1) Durability, divisibility, Acceptability , uniformity
Every integer is divisible by 1. So 1 is a factor. The number ends in a 2 and so is even. Therefore, 2 is a factor. The sum of the digits is 3+1+2 = 6 which is divisible by 3 so 3 is a factor. 2 and 3 are both factors so 2*3 = 6 is a factor. So, four factors are 1, 2, 3 and 6.
780 is divisible by 2 because it's even. 780 is divisible by 3 because its digits total a multiple of 3. 780 is divisible by 5 because it ends in a 0. 780 is divisible by 10 because it ends in a 0.
Since 62 is a composite number and not prime you can check for divisibility by 31 and 2. To check for divisibility by 31 take the last digit of your number and multiply it by four, then add the result to your original number, deleting the last number ex. 624 to test would be 62 + (4*4) = 78 you continue in this fashion until a multiple of 31 and 2 are found. If they are not than it is not a multiple of 62 sources: I am a human calculator, experience