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ways of getting 14

1,1,6,6 6 arrangements (1,6,1,6; 1,6,6,1; 1,1,6,6; 6,6,1,1; 6,1,6,1; 6,1,1,6)

1,2,5,6 24 arr.

1,3,4,6 24 arr.

1,3,5,5 12 arr.

1,4,4,5 12 arr.

2,2,4,6 12 arr.

2,2,5,5 6 arr.

2,3,3,6 12 arr.

2,3,4,5 24 arr.

2,4,4,4 4 arr.

3,3,3,5 4 arr.

3,3,4,4 6 arr.

Total: 146

146*(1/6)4 = 0.1127... so slightly over 1/9

Q: What are odds of rolling 14 with 4 dice?

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The odds are 1:3. The probability is 1/4 or 25%.

The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%

The odds of rolling any number in one roll of one die is 1 in 1. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll is 1 in 1 times 1 in 6, or 1 in 6.Now, look at the second pair of dice. The odds of rolling any number other than a number on the first pair is 5 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not the pair in the first roll is 5 in 6 times 1 in 6, or 5 in 36.Now, look at the third pair of dice. The odds of rolling any number other than a number on the first two pairs is 4 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not one of the first two pairs is 4 in 6 times 1 in 6, or 4 in 36.To compute the total odds of rolling three pairs of numbers using 6 dice, simply multiply these odds together. That is 1 in 6 times 5 in 36 times 4 in 36, or 30 in 7776. Reducing that to lowest common fraction, you get 5 in 1296.(This calculation assumes that the three pairs are different. If two or three of the pairs are allowed to be the same, the computation is different.)

When rolling 2 dice there are 36 combinations that can occur. Sums will range from 2 to 12; sums divided by 4 are 4, 8, and 12 You can get this by dice combinations of 1 3 3 1 2 2 4 4 2 6 6 2 3 5 5 3 6 6 That is 9 ways. so odds are 9/36 = 1 in 4

(1/6)(1/6)(1/6) = 1/216 Tha'ts the total number of outcomes. Now have a look at the possible combinations, describes as [die1] [die2] [die3] 344 434 443 That means the odds are (216/3=) 1/72 chance of rolling 3, 4, 4. with three dice.

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It is 20/36 = 5/9.

The odds are 1:3. The probability is 1/4 or 25%.

The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%

The probability that there will be EXACTLY one five when four dice are rolled is 500/1296 = 125/324, or about 38.58%. The odds are 199 to 125 against, or about 8 to 5. The probability that there will be AT LEAST one five when four dice are rolled is 671/1296, or about 51.77%. The odds are 625 to 671 against, or about 14 to 15.

The odds of rolling any number in one roll of one die is 1 in 1. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll is 1 in 1 times 1 in 6, or 1 in 6.Now, look at the second pair of dice. The odds of rolling any number other than a number on the first pair is 5 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not the pair in the first roll is 5 in 6 times 1 in 6, or 5 in 36.Now, look at the third pair of dice. The odds of rolling any number other than a number on the first two pairs is 4 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not one of the first two pairs is 4 in 6 times 1 in 6, or 4 in 36.To compute the total odds of rolling three pairs of numbers using 6 dice, simply multiply these odds together. That is 1 in 6 times 5 in 36 times 4 in 36, or 30 in 7776. Reducing that to lowest common fraction, you get 5 in 1296.(This calculation assumes that the three pairs are different. If two or three of the pairs are allowed to be the same, the computation is different.)

When rolling 2 dice there are 36 combinations that can occur. Sums will range from 2 to 12; sums divided by 4 are 4, 8, and 12 You can get this by dice combinations of 1 3 3 1 2 2 4 4 2 6 6 2 3 5 5 3 6 6 That is 9 ways. so odds are 9/36 = 1 in 4

(1/6)(1/6)(1/6) = 1/216 Tha'ts the total number of outcomes. Now have a look at the possible combinations, describes as [die1] [die2] [die3] 344 434 443 That means the odds are (216/3=) 1/72 chance of rolling 3, 4, 4. with three dice.

If its a fair dice 1/6

Assuming you are rolling a six-sided dice, it is 1/3 for one dice and 2/3 for two dice.

1 in 6.

-4

It would be 1/6 with 1 dice. To get 5 out of FIVE it would be 1/6 X 1/6 x 1/6 X 1/6 X 1/6 = 1/7776 odds. 4/5 would be 1/216