5 out of 6
there is a probability of 1/6.Answer:For two dice to show 5 and 2:There are two ways to roll a "good" number (2 or 5) for the first dice. This gives odds of 2/6.For the second dice there is one way to role a good number ( 1 in 6)The odds to roll both a 2 and a 5 are (2/6)x(1/6) or 2/36 or 1/18.
The odds of rolling a 7 with two dice is 6 in 36, or 1 in 6.Two six-sided dice will yield 36 different possible combinations in one roll. Note that rolling 1 and 6 is not the same as rolling 6 and 1. Yes, they both equal 7, but for the purposes of determining probability, each throw is unique. There are 6 possible ways to throw a 7, and they are 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1. With 36 different possible outcomes, that means that 6 in 36 of those outcomes results in a 7. The odds of getting a 7 are 6 in 36, or 1 in 6 (reducing the two terms).We sometimes see the terms "odds" and "probability" interchanged, but it is important to distinguish them mathematically. If you are interested in the probability of rolling a 7 in a single roll of a pair of dice, use the link to the Related question.
1/6= 2 because there is only one 2. Therefore the theoretical probability of not rolling a two is the same as everything but two so 5/6.
The first die can come up in any one of 6 ways.The second die can come up in any one of 6 ways.There are (6 x 6) = 36 different ways that two dice can fall.There are 5 ways that they can come up as a six:1 + 55 + 12 + 44 + 23 + 3The probability of rolling a 6 is (5/36) = 13.89 %The odds in favor are 5 to 31.
5 out of 6
2 out of 12
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
Impossible, you can't get 1-6 with only 5 dice.
It is 20/36 = 5/9.
The probability is 5/12.
The probability is approx 0.1608
The odds of rolling 5 ones is 1/6 *1/6 *1/6 *1/6 *1/6 = 1/7776
The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%
well there are 6 sides and the odd of hitting one is a 1 out of 6 chance. the odds of hitting five is a 5 out 6 chance
The odds of rolling any number in one roll of one die is 1 in 1. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll is 1 in 1 times 1 in 6, or 1 in 6.Now, look at the second pair of dice. The odds of rolling any number other than a number on the first pair is 5 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not the pair in the first roll is 5 in 6 times 1 in 6, or 5 in 36.Now, look at the third pair of dice. The odds of rolling any number other than a number on the first two pairs is 4 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not one of the first two pairs is 4 in 6 times 1 in 6, or 4 in 36.To compute the total odds of rolling three pairs of numbers using 6 dice, simply multiply these odds together. That is 1 in 6 times 5 in 36 times 4 in 36, or 30 in 7776. Reducing that to lowest common fraction, you get 5 in 1296.(This calculation assumes that the three pairs are different. If two or three of the pairs are allowed to be the same, the computation is different.)
The probability of rolling exactly one six is equal to: 1/6 * 5/6 * 5/6, which is equal to 25/216, or 11.5740741 percent.