It is 20/36 = 5/9.
The probability of rolling two even numbers on two standard dice is 0.52, or 0.25.
There is a one out of four chance of having both dice even numbers.
The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.===================================Opinion #2:-- There are 36 possible outcomes when 2 dice are rolled.-- Only one of the outcomes is a 2.-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .-- The 'odds' are 1,011 to 989 against it.
The odds of rolling a 7 are 1/6. The odds of rolling two in a row are 1/36. The odds of rolling an 11 are 1/18. The odds of rolling two in a row are 1/324. The odds of rolling doubles are 1/6. The odds of rolling double twice in a row are 1/36.
The odds are 1 in 36 that you will roll a sum of 2 in a single roll of two fair dice.
1 in 6. Basically dice 1 can roll any number So the odds are that dice 2 has the same number as dice 1, or 1 in 6
The odds are 1:3. The probability is 1/4 or 25%.
2 of 12
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
The probability is 5/12.
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
The odds of rolling any number in one roll of one die is 1 in 1. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll is 1 in 1 times 1 in 6, or 1 in 6.Now, look at the second pair of dice. The odds of rolling any number other than a number on the first pair is 5 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not the pair in the first roll is 5 in 6 times 1 in 6, or 5 in 36.Now, look at the third pair of dice. The odds of rolling any number other than a number on the first two pairs is 4 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not one of the first two pairs is 4 in 6 times 1 in 6, or 4 in 36.To compute the total odds of rolling three pairs of numbers using 6 dice, simply multiply these odds together. That is 1 in 6 times 5 in 36 times 4 in 36, or 30 in 7776. Reducing that to lowest common fraction, you get 5 in 1296.(This calculation assumes that the three pairs are different. If two or three of the pairs are allowed to be the same, the computation is different.)