6.12,18,24,30,36 just go through the 3 multiplication facts and find the even ones and there's your answer.
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
List the numbers: 216, 360 Divide both numbers by 2, since they are both divisible by 2: 108, 180 Divide both numbers by 2 again, since they are both divisible by 2: 54, 90 Divide both numbers by 2 yet again, since they are both divisible by 2: 27, 45 Divide both numbers by 3, since they are both divisible by 3: 9, 15 Divide both numbers by 3 again, since they are both divisible by 3: 3, 5 Since 3 and 5 do not have any common factors greater than 1, we can now multiply all the numbers we divided by: 2 x 2 x 2 x 3 x 3 = 8 x 9 = 72 GCF(216, 360)=72
1, 2 and 3
Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
Numbers are divisible by 6 if they are divisible by both 2 and 3.All even numbers are divisible by 2. Odd numbers are not.To see if a number is divisible by 3, add the individual digits of the number to each other and see if that number is divisible by 3. If it is, then the original number is also divisible by 3.Example: 2712, add 2+7+1+2=12 Is 12 divisible by 3? Yes. Therefore, 2712 is divisible by 3.The number 2712 is also divisible by 2, since it is an even number.Now you know that 2712 is divisible by 6.
What numbers are only divisible by 2 and 3 .
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
670
Only 66.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
Even numbers are divisible by 2. Even numbers that are divisible by 3 must be divisible by 2 and by 3, so they have to be divisible by 2 x 3.6, 12, 18, 24 …