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I assume you mean (x-7)^2 + (y + 6)^2 = 100 (using "^" for powers). Answers.com eliminates some signs, such as the equal sign.

This equation is in a form in which you can (almost) read off this information directly. A circle with equation (x - a)^2 + (y - b)^2 = r^2 has a center (a, b), and a radius of "r". In this case, just convert the original equation to:

(x - 7)^2 + (y - (-6))^2 = 10^2

And you can directly read off the coordinates of the center (7, -6), and of the radius (10).

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To determine the center and radius of a circle described by an equation in the form "(x-h)^2 + (y-k)^2 = r^2", we need to rewrite the given equation in that form. The equation (x-7)^2 + (y-6)^2 = 2100 is already in that form. Therefore, the center of the circle is at the point (7, 6) and the radius is the square root of 2100.

Q: What are the center and radius of the circle described by the equation (x-7)2 (y 6)2100?

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Center of circle: (6, 8) Radius of circle: 3

I think it is center: (-4, 3) ; radius: 2 Apex:)

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2

depends on the equation.

this is impossible

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Center of circle: (6, 8) Radius of circle: 3

I think it is center: (-4, 3) ; radius: 2 Apex:)

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2

depends on the equation.

The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

this is impossible

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The equation of the circle is: x^2 + y^2 = 81

Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4

x2 + y2 = 64

x2 + y2 = 81