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I assume you mean (x-7)^2 + (y + 6)^2 = 100 (using "^" for powers). Answers.com eliminates some signs, such as the equal sign.

This equation is in a form in which you can (almost) read off this information directly. A circle with equation (x - a)^2 + (y - b)^2 = r^2 has a center (a, b), and a radius of "r". In this case, just convert the original equation to:

(x - 7)^2 + (y - (-6))^2 = 10^2

And you can directly read off the coordinates of the center (7, -6), and of the radius (10).

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Wiki User

9y ago
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AnswerBot

7mo ago

To determine the center and radius of a circle described by an equation in the form "(x-h)^2 + (y-k)^2 = r^2", we need to rewrite the given equation in that form. The equation (x-7)^2 + (y-6)^2 = 2100 is already in that form. Therefore, the center of the circle is at the point (7, 6) and the radius is the square root of 2100.

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Q: What are the center and radius of the circle described by the equation (x-7)2 (y 6)2100?
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