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Q: What is the equation of a circle with center (3 8) and a radius of 2?

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Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

depends on the equation.

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2

The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

Center of circle: (6, 8) Radius of circle: 3

The equation of the circle is: x^2 + y^2 = 81

Equation of circle: (x-2)^2 +(y+9)^2 = 49

x² + y² = 4.

If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4

center 5,-3 radius 4

The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49

The equation is: (x -0)^2 +(y -2)^2 = 121

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